夏尔丹作品名字:解方程 (2x+1)^2+3(x-2)^2-4=7(x+3)(x-3)
来源:百度文库 编辑:中科新闻网 时间:2024/05/19 23:12:05
解:4x^2+4x+1+3(x^2-4x+4)-4=7(x^2-9)
7x^2-8x+9=7x^2-63
-8x=-72
x=9
先展开得:
4x^2+4x+1+3x-12x+12-4=7x^2-63
-8x+9=-63
8x=72
x=9
解:4x^2+4x+1+3(x^2-4x+4)-4=7(x^2-9)
7x^2-8x+9=7x^2-63
-8x=-72
x=9
先展开得:
4x^2+4x+1+3x-12x+12-4=7x^2-63
-8x+9=-63
8x=72
x=9