4a^2+4a+b^2-6b+10=04a^2+4a+1+b^2-6b+9=0(2a+1)^2+(b-3)^2=02a+1=0,b-3=0a=-1/2,b=3a^3b+ab^3=(-1/2)^3*3+(-1/2)*3^3=-111/8
(2a+1)^2+(b-3)^2=0∴a=-1/2,b=3原式=-111/8