手工子线打结器:根式(写出详细过程)

来源:百度文库 编辑:中科新闻网 时间:2024/05/17 01:26:40
计算:
(1+2的负1/32次方)X(1+2的负1/16次方)X(1+2的负1/8次方)X(1+2的负1/4次方)X(1+2的负1/2次方)

(1+2的负1/32次方)×(1+2的负1/16次方)×(1+2的负1/8次方)×(1+2的负1/4次方)×(1+2的负1/2次方)=(1-2的负1/32次方)×(1+2的负1/32次方)×(1+2的负1/16次方)×(1+2的负1/8次方)×(1+2的负1/4次方)×(1+2的负1/2次方)÷(1-2的负1/32次方)=(1-2的负1/16次方)×(1+2的负1/16次方)×(1+2的负1/8次方)×(1+2的负1/4次方)×(1+2的负1/2次方)÷(1-2的负1/32次方)=(1-2的负1/8次方)×(1+2的负1/8次方)×(1+2的负1/4次方)×(1+2的负1/2次方)÷(1-2的负1/32次方)=(1-2的负1/4次方)×(1+2的负1/4次方)×(1+2的负1/2次方)÷(1-2的负1/32次方)=(1-2的负1/2次方)×(1+2的负1/2次方)÷(1-2的负1/32次方)=(1-2的负1次方)÷(1-2的负1/32次方)

拜托~ 也太能折腾人了吧 郁闷~

能不能翻成数学语言