(x^2-x-5)/(x+2)=[(x+2)(x-3)+1]/(x+2)=(x-3)+1/(x+2)=(x+2)+1/(x+2)-5≥2-5=-3所以最小值是-3注:题目要限制x>-2
X+2≠0X≠-2(X^2-x-5)/(x+2)=(X-3)(X+2)/(X+2)=X-3无最小值