工商银行app查询开户行:分解因式(x^2-2x)^2+2x^2-4x+1

来源:百度文库 编辑:中科新闻网 时间:2024/06/04 04:02:55
谢谢帮忙

(x^2-2x)^2+2x^2-4x+1
=(x^2-2x)^2+2(x^2-2x)+1
=(x^2-2x+1)^2
=(x-1)^4

x^2-2x)^2+2x^2-4x+1
=x^2( x-2)^2+2x(x-2)+1
[x(x-2)+1]^2
=[x^2-2x+1]^2
=(x-1)^4