招商代理加盟会:化简,求值

来源:百度文库 编辑:中科新闻网 时间:2024/05/03 02:05:37
[(x+2y)^2 -(x+y)(3x-y)-5y^2]÷2x,其中x=-2,y=1/2

[(x+2y)^2 -(x+y)(3x-y)-5y^2]÷2x
=[x^2+4xy+4y^2-(3x^2+2xy-y^2)-5y^2]÷2x
=[-2x^2+2xy]÷2x
=-x+y
=-(-2)+1/2
=5/2

(x^2+2xy+4y^2-3x^2-2xy+y^2-5y^2)/2x=-2x^2/2x=-x

所以=2