厦门小吃培训中心:C语言,进制转换题。悬赏。。

#include<stdio.h>
#include<math.h>
void main()
{
int a,N,j,i=0,k=0;
int t[16];
printf("shu ru yi shi jin zhi shu:");
scanf("%d",&a);
printf("\nba jin zhi：%o",a); //shu chu ba jin zhi xing shi
printf("\nshi liu jin zhi：%x",a);//shu chu shi liu jin zhi xing shi
N=a; //yi xia yong lai shu chu er jin zhi xing shi
for(;a/2!=0;a=a/2) //tong jishi jin zhi shu zhuan hua wei er jin zhi shu zhan ji wei
i++;
a=N;
for(j=0;j<=i;j++) //qiu de er jin zhi shu
{
t[j]=a%2;
a=a/2;
}
printf("\ner jin zhi shu :"); //shu chu er jin zhi shu
for(j=i;j>=0;j--)
{
printf("%d",t[j]);
}
}

函数为：
main()
{
int a;
printf("输入十进制数字:");
scanf("%d",&a);
printf("\n八进制：%o",a);
printf("\n十六进制：%x",a);
}
此函数不全，还有须改的地方，希望“哈来了"自己能看看C语言书，其实这很简单的！

char *itoa( int value, char *string, int radix );
radix

Base of value; must be in the range 2 – 36