黑夜传说2在线:数学题(急的N次方)

来源:百度文库 编辑:中科新闻网 时间:2024/04/28 12:56:05
一个正整数,除以5余1,除以7余2,除以9余3,除以11余4,求此数最小值。请求大侠们赐予我一套简便算法。

多项式f(x)除以x-b所得的余数等于f(b).

例 f(x)=3x3-2x2-4x-3除以x+1所得的余数就是f(-1)=-4.

f(x)=ax4+bx3-dx+e除以(x+m)的余数是f(-m)=am4-bm3+dm+e.

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设这个正整数为X,可得5X+1=7X+2=9X+3=11X+4去解吧~!!