亚洲天使vip视频mp4:1题数学,急!

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已知 1/X +1/Y =5
求(2X-3XY+2Y)/(X+2XY+Y)的值.

化简
(2X-3XY+2Y)/(X+2XY+Y)
=(2X+4XY+2Y-7XY)/(X+2XY+Y)
=2-7XY/(X+2XY+Y)
=2-7/(1/Y+2+1/X)
=2-1
1

(2X-3XY+2Y)/(X+2XY+Y) x、y不为0,则分子分母同提xy公因式相销
=(2/y-3+2/x)/(1/y+2+1/x)
=(10-3)/(5+2)
=1

上下同时除以XY,得2(1/X+1/Y)-3 分母为(1/X+1/Y)+2

解:因为1/X +1/Y =5
(X+Y)/XY=5
X+Y=5XY
所以(2X-3XY+2Y)/(X+2XY+Y)=(10XY-3XY)/(5XY+2XY)=7XY/7XY=1