音乐剧狮子王剧情介绍:在斜三角形ABC中求证:ctgA/2+ctgB/2+ctgC/2=ctgA/2×ctgB/2×ctgC/2

来源:百度文库 编辑:中科新闻网 时间:2024/05/08 02:52:59
希望有详细过程,拜托了。

先证:tga/2*tgb/2+tgb/2*tgc/2+tgc/2*tga/2=1
tga/2*tgb/2+tgb/2*tgc/2+tgc/2*tga/2
=tga/2*tgb/2+tgc/2*(tga/2+tgb/2)
=tga/2*tgb/2+tg[90-(a+b)/2]*(tga/2+tgb/2)
=tga/2*tgb/2+ct(a/2+b/2)*(tga/2+tgb/2)
=tga/2*tgb/2+(tga/2+tgb/2)/tg(a/2+b/2)
=tga/2*tgb/2+1-tga/2*tgb/2
=1
将余切化成正切,即可得
ctgA/2+ctgB/2+ctgC/2=ctgA/2×ctgB/2×ctgC/2