多肉广寒宫怎么繁殖:请教一个算法

来源:百度文库 编辑:中科新闻网 时间:2024/05/15 23:17:22
请教一个算法,语言C or C++ or Pascal,
编写一个程序,使得能够输出自身源代码,但是不能利用源文件。

#include <stdio.h>

char c[] = {0x7d,0x3b,0xa,0x69,0x6e,0x74,0x20,0x6d,0x61,0x69,0x6e,0x28,0x29,0xa,0x7b,0xa,0x20,0x20,0x20,0x20,0x70,0x72,0x69,0x6e,0x74,0x66,0x28,0x22,0x23,0x69,0x6e,0x63,0x6c,0x75,0x64,0x65,0x20,0x3c,0x73,0x74,0x64,0x69,0x6f,0x2e,0x68,0x3e,0x5c,0x6e,0x63,0x68,0x61,0x72,0x20,0x63,0x5b,0x5d,0x20,0x3d,0x20,0x7b,0x22,0x29,0x3b,0xa,0x20,0x20,0x20,0x20,0x66,0x6f,0x72,0x28,0x69,0x6e,0x74,0x20,0x69,0x3d,0x30,0x3b,0x69,0x3c,0x73,0x69,0x7a,0x65,0x6f,0x66,0x28,0x63,0x29,0x3b,0x2b,0x2b,0x69,0x29,0xa,0x20,0x20,0x20,0x20,0x7b,0xa,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x20,0x70,0x72,0x69,0x6e,0x74,0x66,0x28,0x22,0x30,0x78,0x25,0x78,0x2c,0x22,0x2c,0x63,0x5b,0x69,0x5d,0x29,0x3b,0xa,0x20,0x20,0x20,0x20,0x7d,0xa,0x20,0x20,0x20,0x20,0x70,0x72,0x69,0x6e,0x74,0x66,0x28,0x22,0x25,0x73,0x22,0x2c,0x63,0x29,0x3b,0xa,0x20,0x20,0x20,0x20,0x72,0x65,0x74,0x75,0x72,0x6e,0x20,0x30,0x3b,0xa,0x7d,};

int main()

{

printf("#include <stdio.h>\nchar c[] = {");

for(int i=0;i<sizeof©;++i)

{

printf("0x%x,",c[i]);

}

printf("%s",c);

return 0;

}

我想是这样的,如果不利用自身源代码,就需要以已经编译完的可执行程序为根据还原出源程序,可这样只能反汇编成汇编语言,要完全输出自身源码好像不大可能.

使得能够输出自身源代码,只能是反汇编,或狗屁不通的C
不能利用源文件,输出自身源代码,不可能