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来源：百度文库编辑：中科新闻网时间：2024/05/06 20:42:02

分解因式
x的4次方+2000x+1999x的2次方+1999
一楼:x^3 + 1=(x - 1)(x^2 + x + 1)
?????????????????????????????????
好象是x^3 + 1=(x +1)(x^2 - x + 1)吧

x^4 + 2000x + 1999x^2 + 1999
= x^4 + x + 1999(x^2 + x + 1)
= x(x^3 + 1) + 1999(x^2 + x + 1)
唉....不行啊
= x(x - 1)(x^2 + x + 1) + 1999(x^2 + x + 1)
= (x^2 - x + 1999)(x^2 + x + 1)

x^4 + 2000x + 1999x^2 + 1999
= x^4 + x + 1999(x^2 + x + 1)
= x(x^3 + 1) + 1999(x^2 + x + 1)

= x(x - 1)(x^2 + x + 1) + 1999(x^2 + x + 1)
= (x^2 - x + 1999)(x^2 + x + 1)

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