炉石战网积分如何兑换:救命!数学题!
来源:百度文库 编辑:中科新闻网 时间:2024/05/11 05:22:29
设x+y+z=A(x+2y+3z)+B(4x+3y+2z)
=(A+4B)x+(2A+3B)y+(3A+2B)z
A+4B=1
2A+3B=1
3A+2B=1
A=1/5,B=1/5
x+y+z
=1/5*(10+15)
=5
设x+y+z=A(x+2y+3z)+B(4x+3y+2z)
=(A+4B)x+(2A+3B)y+(3A+2B)z
A+4B=1
2A+3B=1
3A+2B=1
A=1/5,B=1/5
x+y+z
=1/5*(10+15)
=5