游击英雄演员高雅:初一数学

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已知1/(x(x+2))=(1/2)(A/x-B/(x+2)),求A,B的值

1/(x(x+2)) = (1/2) * (1/x - 1/(x+2))

(1/2) * (1/x - 1/(x+2)) = (1/2) * (A/x-B/(x+2))

1/x - 1/(x+2) = A/x-B/(x+2)

A=1
B=1

令 x=1,得3A-B=2
令 x=-1,得A+B=2
解得,A=1,B=1