吕光明书法价格:一道计算题 急用

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化简或求值:(x-1)(x+1)(x^2+1)(x^4+1) (要步骤)

(x-1)(x+1)(x^2+1)(x^4+1)
=(x^2-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1

(x-1)(x+1)(x^2+1)(x^4+1)
=(x^2-1)(X^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1

靠 没抄袭,这种题过程都一样

解:原式=(x^2-1(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1
(不许抄袭啊!!!)

(x-1)(x+1)(x^2+1)(x^4+1)
=(x^-1)(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1

原式=(x^2-1(x^2+1)(x^4+1)
=(x^4-1)(x^4+1)
=x^8-1